फलन (f(x)=\sqrt{x+2}+\sqrt{6-x}) का अधिकतम मान क्या है?
What is the maximum value of (f(x)=\sqrt{x+2}+\sqrt{6-x})?
Explanation opens after your attempt
A. (4)
Concept
On ([-2,6]), the sum is symmetric and maximum occurs at (x=2). Then the value is \(\sqrt{4}+\sqrt{4}=4\).
Why this answer is correct
The correct answer is A. (4). On ([-2,6]), the sum is symmetric and maximum occurs at (x=2). Then the value is \(\sqrt{4}+\sqrt{4}=4\).
Exam Tip
प्रांत ([-2,6]) पर योग सममित है और अधिकतम (x=2) पर मिलता है। तब मान \(\sqrt{4}+\sqrt{4}=4\) है।
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