फलन \(y=\sqrt{16-x^2}\) का डोमेन क्या है?
What is the domain of \(y=\sqrt{16-x^2}\)?
Explanation opens after your attempt
A. ([-4,4])
Concept
For the square root, \(16-x^2\ge 0\) is required. This gives \(-4\le x\le 4\).
Why this answer is correct
The correct answer is A. ([-4,4]). For the square root, \(16-x^2\ge 0\) is required. This gives \(-4\le x\le 4\).
Exam Tip
वर्गमूल के लिए \(16-x^2\ge 0\) चाहिए। इससे \(-4\le x\le 4\) मिलता है।
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