फलन \(y=\sqrt{16-x^2}\) का डोमेन क्या है?

What is the domain of \(y=\sqrt{16-x^2}\)?

Explanation opens after your attempt
Correct Answer

A. ([-4,4])

Step 1

Concept

For the square root, \(16-x^2\ge 0\) is required. This gives \(-4\le x\le 4\).

Step 2

Why this answer is correct

The correct answer is A. ([-4,4]). For the square root, \(16-x^2\ge 0\) is required. This gives \(-4\le x\le 4\).

Step 3

Exam Tip

वर्गमूल के लिए \(16-x^2\ge 0\) चाहिए। इससे \(-4\le x\le 4\) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

फलन \(y=\sqrt{16-x^2}\) का डोमेन क्या है? / What is the domain of \(y=\sqrt{16-x^2}\)?

Correct Answer: A. ([-4,4]). Explanation: वर्गमूल के लिए \(16-x^2\ge 0\) चाहिए। इससे \(-4\le x\le 4\) मिलता है। / For the square root, \(16-x^2\ge 0\) is required. This gives \(-4\le x\le 4\).

Which concept should I revise for this Mathematics MCQ?

For the square root, \(16-x^2\ge 0\) is required. This gives \(-4\le x\le 4\).

What exam hint can help solve this Mathematics question?

वर्गमूल के लिए \(16-x^2\ge 0\) चाहिए। इससे \(-4\le x\le 4\) मिलता है।