फलन (f(x)=\sqrt{7-2x}) के ग्राफ का प्रांत क्या है?

What is the domain of the graph of (f(x)=\sqrt{7-2x})?

Explanation opens after your attempt
Correct Answer

A. (\left\(-\infty,\frac{7}{2}\right]\)

Step 1

Concept

For the square root, \(7-2x\ge 0\), so \(x\le \frac{7}{2}\). In exams, keep the expression inside the square root non-negative.

Step 2

Why this answer is correct

The correct answer is A. (\left\(-\infty,\frac{7}{2}\right]\). For the square root, \(7-2x\ge 0\), so \(x\le \frac{7}{2}\). In exams, keep the expression inside the square root non-negative.

Step 3

Exam Tip

वर्गमूल के लिए \(7-2x\ge 0\) इसलिए \(x\le \frac{7}{2}\)। परीक्षा में वर्गमूल के अंदर की राशि अनऋणात्मक रखें।

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Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=\sqrt{7-2x}) के ग्राफ का प्रांत क्या है? / What is the domain of the graph of (f(x)=\sqrt{7-2x})?

Correct Answer: A. (\left\(-\infty,\frac{7}{2}\right]\). Explanation: वर्गमूल के लिए \(7-2x\ge 0\) इसलिए \(x\le \frac{7}{2}\)। परीक्षा में वर्गमूल के अंदर की राशि अनऋणात्मक रखें। / For the square root, \(7-2x\ge 0\), so \(x\le \frac{7}{2}\). In exams, keep the expression inside the square root non-negative.

Which concept should I revise for this Mathematics MCQ?

For the square root, \(7-2x\ge 0\), so \(x\le \frac{7}{2}\). In exams, keep the expression inside the square root non-negative.

What exam hint can help solve this Mathematics question?

वर्गमूल के लिए \(7-2x\ge 0\) इसलिए \(x\le \frac{7}{2}\)। परीक्षा में वर्गमूल के अंदर की राशि अनऋणात्मक रखें।