असमानता \(x-3y\le9\) में (y) के रूप में सही रूप कौन सा है?

What is the correct form in terms of (y) for \(x-3y\le9\)?

Explanation opens after your attempt
Correct Answer

A. \(y\ge\frac{x-9}{3}\)

Step 1

Concept

From \(x-3y\le9\), we get \(-3y\le9-x\), hence \(y\ge\frac{x-9}{3}\). Dividing by a negative reverses the sign.

Step 2

Why this answer is correct

The correct answer is A. \(y\ge\frac{x-9}{3}\). From \(x-3y\le9\), we get \(-3y\le9-x\), hence \(y\ge\frac{x-9}{3}\). Dividing by a negative reverses the sign.

Step 3

Exam Tip

\(x-3y\le9\) से \(-3y\le9-x\), इसलिए \(y\ge\frac{x-9}{3}\) है। ऋणात्मक से भाग देने पर चिन्ह उलटता है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

असमानता \(x-3y\le9\) में (y) के रूप में सही रूप कौन सा है? / What is the correct form in terms of (y) for \(x-3y\le9\)?

Correct Answer: A. \(y\ge\frac{x-9}{3}\). Explanation: \(x-3y\le9\) से \(-3y\le9-x\), इसलिए \(y\ge\frac{x-9}{3}\) है। ऋणात्मक से भाग देने पर चिन्ह उलटता है। / From \(x-3y\le9\), we get \(-3y\le9-x\), hence \(y\ge\frac{x-9}{3}\). Dividing by a negative reverses the sign.

Which concept should I revise for this Mathematics MCQ?

From \(x-3y\le9\), we get \(-3y\le9-x\), hence \(y\ge\frac{x-9}{3}\). Dividing by a negative reverses the sign.

What exam hint can help solve this Mathematics question?

\(x-3y\le9\) से \(-3y\le9-x\), इसलिए \(y\ge\frac{x-9}{3}\) है। ऋणात्मक से भाग देने पर चिन्ह उलटता है।