\(\frac{n!}{a!b!c!}\) को \({}^{n}C_a{}^{n-a}C_b\) से जोड़ने की शर्त क्या है?
What condition connects \(\frac{n!}{a!b!c!}\) with \({}^{n}C_a{}^{n-a}C_b\)?
Explanation opens after your attempt
Correct Answer
A. (a+b+c=n)
Concept
Choose (a) first, then (b) from the remaining, and (c) is automatically fixed. In exams match sequential selection with factorial form.
Why this answer is correct
The correct answer is A. (a+b+c=n). Choose (a) first, then (b) from the remaining, and (c) is automatically fixed. In exams match sequential selection with factorial form.
Exam Tip
पहले (a) चुनें, फिर बचे में से (b), और (c) अपने आप तय होता है। परीक्षा में sequential selection को factorial form से मिलाएं।
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