\((U={1,2,3,\ldots,72}), (A={x:x\) 6 से विभाज्य है\(}) और (B={x:x\) 8 से विभाज्य है}) हैं। \((n(A\cup B)) कितना है\)?

\((U={1,2,3,\ldots,72}), (A={x:x\) is divisible by \(6}), and (B={x:x\) is divisible by \(8}). What is (n(A\cup B))\)?

Explanation opens after your attempt
Correct Answer

B. (18)

Step 1

Concept

Multiples of (6) are (12), multiples of (8) are (9), and multiples of (24) are (3), so (12+9-3=18). Use the LCM for the common part.

Step 2

Why this answer is correct

The correct answer is B. (18). Multiples of (6) are (12), multiples of (8) are (9), and multiples of (24) are (3), so (12+9-3=18). Use the LCM for the common part.

Step 3

Exam Tip

(6) के गुणज (12), (8) के गुणज (9) और (24) के गुणज (3) हैं, इसलिए (12+9-3=18)। साझा भाग के लिए लघुत्तम समापवर्त्य लें।

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Mathematics Answer, Explanation and Revision Hints

\((U={1,2,3,\ldots,72}), (A={x:x\) 6 से विभाज्य है\(}) और (B={x:x\) 8 से विभाज्य है}) हैं। (n\(A\cup B\)) कितना है? \(/ (U={1,2,3,\ldots,72}), (A={x:x\) is divisible by \(6}), and (B={x:x\) is divisible by \(8}). What is (n(A\cup B))\)?

Correct Answer: B. (18). Explanation: (6) के गुणज (12), (8) के गुणज (9) और (24) के गुणज (3) हैं, इसलिए (12+9-3=18)। साझा भाग के लिए लघुत्तम समापवर्त्य लें। / Multiples of (6) are (12), multiples of (8) are (9), and multiples of (24) are (3), so (12+9-3=18). Use the LCM for the common part.

Which concept should I revise for this Mathematics MCQ?

Multiples of (6) are (12), multiples of (8) are (9), and multiples of (24) are (3), so (12+9-3=18). Use the LCM for the common part.

What exam hint can help solve this Mathematics question?

(6) के गुणज (12), (8) के गुणज (9) और (24) के गुणज (3) हैं, इसलिए (12+9-3=18)। साझा भाग के लिए लघुत्तम समापवर्त्य लें।