\((U={1,2,3,\ldots,60}), (A={x:x\) is divisible by \(2}), (B={x:x\) is divisible by \(3}) और (C={x:x\) is divisible by 5}) हैं। \((n(A\cap B\cap C)) कितना है\)?

\((U={1,2,3,\ldots,60}), (A={x:x\) is divisible by \(2}), (B={x:x\) is divisible by \(3}), and (C={x:x\) is divisible by \(5}). What is (n(A\cap B\cap C))\)?

Explanation opens after your attempt
Correct Answer

B. (2)

Step 1

Concept

To be in all three sets, a number must be divisible by (30), namely (30,60). Hence the count is (2).

Step 2

Why this answer is correct

The correct answer is B. (2). To be in all three sets, a number must be divisible by (30), namely (30,60). Hence the count is (2).

Step 3

Exam Tip

तीनों में आने के लिए संख्या (30) से विभाज्य होगी, यानी (30,60)। इसलिए संख्या (2) है।

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Mathematics Answer, Explanation and Revision Hints

\((U={1,2,3,\ldots,60}), (A={x:x\) is divisible by \(2}), (B={x:x\) is divisible by \(3}) और (C={x:x\) is divisible by 5}) हैं। (n\(A\cap B\cap C\)) कितना है? \(/ (U={1,2,3,\ldots,60}), (A={x:x\) is divisible by \(2}), (B={x:x\) is divisible by \(3}), and (C={x:x\) is divisible by \(5}). What is (n(A\cap B\cap C))\)?

Correct Answer: B. (2). Explanation: तीनों में आने के लिए संख्या (30) से विभाज्य होगी, यानी (30,60)। इसलिए संख्या (2) है। / To be in all three sets, a number must be divisible by (30), namely (30,60). Hence the count is (2).

Which concept should I revise for this Mathematics MCQ?

To be in all three sets, a number must be divisible by (30), namely (30,60). Hence the count is (2).

What exam hint can help solve this Mathematics question?

तीनों में आने के लिए संख्या (30) से विभाज्य होगी, यानी (30,60)। इसलिए संख्या (2) है।