\(^{n}C_4\) को \(^{n}P_4\) से प्राप्त करने के लिए किससे भाग देंगे?

To obtain \(^{n}C_4\) from \(^{n}P_4\) by what should we divide?

Explanation opens after your attempt
Correct Answer

A. (4!)

Step 1

Concept

The (4!) internal orders of four selected objects must be removed. In exams apply \(^{n}C_r=\frac{^{n}P_r}{r!}\).

Step 2

Why this answer is correct

The correct answer is A. (4!). The (4!) internal orders of four selected objects must be removed. In exams apply \(^{n}C_r=\frac{^{n}P_r}{r!}\).

Step 3

Exam Tip

चार चुनी वस्तुओं के (4!) internal orders हटाने होते हैं। परीक्षा में \(^{n}C_r=\frac{^{n}P_r}{r!}\) लगाएँ।

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Mathematics Answer, Explanation and Revision Hints

\(^{n}C_4\) को \(^{n}P_4\) से प्राप्त करने के लिए किससे भाग देंगे? / To obtain \(^{n}C_4\) from \(^{n}P_4\) by what should we divide?

Correct Answer: A. (4!). Explanation: चार चुनी वस्तुओं के (4!) internal orders हटाने होते हैं। परीक्षा में \(^{n}C_r=\frac{^{n}P_r}{r!}\) लगाएँ। / The (4!) internal orders of four selected objects must be removed. In exams apply \(^{n}C_r=\frac{^{n}P_r}{r!}\).

Which concept should I revise for this Mathematics MCQ?

The (4!) internal orders of four selected objects must be removed. In exams apply \(^{n}C_r=\frac{^{n}P_r}{r!}\).

What exam hint can help solve this Mathematics question?

चार चुनी वस्तुओं के (4!) internal orders हटाने होते हैं। परीक्षा में \(^{n}C_r=\frac{^{n}P_r}{r!}\) लगाएँ।