असमानता \( 6-\frac{x}{3}\geq \frac{2x-1}{2} \) का हल है:
The solution of \( 6-\frac{x}{3}\geq \frac{2x-1}{2} \) is:
Explanation opens after your attempt
Correct Answer
A. \(x\leq \frac{39}{8}\)
Concept
Multiplying by (6) gives \(36-2x\geq 6x-3\). Thus \(39\geq 8x\) and \(x\leq \frac{39}{8}\).
Why this answer is correct
The correct answer is A. \(x\leq \frac{39}{8}\). Multiplying by (6) gives \(36-2x\geq 6x-3\). Thus \(39\geq 8x\) and \(x\leq \frac{39}{8}\).
Exam Tip
(6) से गुणा करने पर \(36-2x\geq 6x-3\) मिलता है। इससे \(39\geq 8x\) और \(x\leq \frac{39}{8}\) है।
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