असमानता \(\frac{3x-2}{4}\geq 4\) को हल कीजिए।

Solve the inequality \(\frac{3x-2}{4}\geq 4\).

Explanation opens after your attempt
Correct Answer

A. \(x\geq 6\)

Step 1

Concept

Multiplying by positive (4) gives \(3x-2\geq 16\), so \(x\geq 6\). A positive denominator does not reverse the sign.

Step 2

Why this answer is correct

The correct answer is A. \(x\geq 6\). Multiplying by positive (4) gives \(3x-2\geq 16\), so \(x\geq 6\). A positive denominator does not reverse the sign.

Step 3

Exam Tip

धनात्मक (4) से गुणा करने पर \(3x-2\geq 16\), इसलिए \(x\geq 6\)। धनात्मक हर से चिन्ह नहीं बदलता।

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Mathematics Answer, Explanation and Revision Hints

असमानता \(\frac{3x-2}{4}\geq 4\) को हल कीजिए। / Solve the inequality \(\frac{3x-2}{4}\geq 4\).

Correct Answer: A. \(x\geq 6\). Explanation: धनात्मक (4) से गुणा करने पर \(3x-2\geq 16\), इसलिए \(x\geq 6\)। धनात्मक हर से चिन्ह नहीं बदलता। / Multiplying by positive (4) gives \(3x-2\geq 16\), so \(x\geq 6\). A positive denominator does not reverse the sign.

Which concept should I revise for this Mathematics MCQ?

Multiplying by positive (4) gives \(3x-2\geq 16\), so \(x\geq 6\). A positive denominator does not reverse the sign.

What exam hint can help solve this Mathematics question?

धनात्मक (4) से गुणा करने पर \(3x-2\geq 16\), इसलिए \(x\geq 6\)। धनात्मक हर से चिन्ह नहीं बदलता।