Pascal identity \(^{n}C_r=^{n-1}C_r+^{n-1}C_{r-1}\) किस counting split से प्राप्त होती है?

Pascal identity \(^{n}C_r=^{n-1}C_r+^{n-1}C_{r-1}\) comes from which counting split?

Explanation opens after your attempt
Correct Answer

A. एक fixed वस्तु शामिल है या शामिल नहीं हैA fixed object is included or not included

Step 1

Concept

Make cases on one fixed object: include it or exclude it. In exams derive such identities by inclusion cases.

Step 2

Why this answer is correct

The correct answer is A. एक fixed वस्तु शामिल है या शामिल नहीं है / A fixed object is included or not included. Make cases on one fixed object: include it or exclude it. In exams derive such identities by inclusion cases.

Step 3

Exam Tip

किसी fixed वस्तु पर case बनाएं: उसे लें या न लें। परीक्षा में ऐसी identities को inclusion case से derive करें।

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Mathematics Answer, Explanation and Revision Hints

Pascal identity \(^{n}C_r=^{n-1}C_r+^{n-1}C_{r-1}\) किस counting split से प्राप्त होती है? / Pascal identity \(^{n}C_r=^{n-1}C_r+^{n-1}C_{r-1}\) comes from which counting split?

Correct Answer: A. एक fixed वस्तु शामिल है या शामिल नहीं है / A fixed object is included or not included. Explanation: किसी fixed वस्तु पर case बनाएं: उसे लें या न लें। परीक्षा में ऐसी identities को inclusion case से derive करें। / Make cases on one fixed object: include it or exclude it. In exams derive such identities by inclusion cases.

Which concept should I revise for this Mathematics MCQ?

Make cases on one fixed object: include it or exclude it. In exams derive such identities by inclusion cases.

What exam hint can help solve this Mathematics question?

किसी fixed वस्तु पर case बनाएं: उसे लें या न लें। परीक्षा में ऐसी identities को inclusion case से derive करें।