समुच्चय \(A=\{1,2,3,4\}\) पर \(R={(a,b):a-b\) (3) से विभाज्य है(}) है। (R) में कितने ordered pairs हैं?

On \(A=\{1,2,3,4\}\), \(R={(a,b):a-b\) is divisible by (3)(}). How many ordered pairs are in (R)?

Explanation opens after your attempt
Correct Answer

A. (6)

Step 1

Concept

The classes are ({1,4},{2},{3}), so the number of pairs is \(2^2+1^2+1^2=6\). Add the squares of the sizes of the equivalence classes.

Step 2

Why this answer is correct

The correct answer is A. (6). The classes are ({1,4},{2},{3}), so the number of pairs is \(2^2+1^2+1^2=6\). Add the squares of the sizes of the equivalence classes.

Step 3

Exam Tip

Classes ({1,4},{2},{3}) हैं, इसलिए pairs की संख्या \(2^2+1^2+1^2=6\) है। Equivalence classes के sizes के squares जोड़ें।

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Mathematics Answer, Explanation and Revision Hints

समुच्चय \(A=\{1,2,3,4\}\) पर \(R={(a,b):a-b\) (3) से विभाज्य है(}) है। (R) में कितने ordered pairs हैं? / On \(A=\{1,2,3,4\}\), \(R={(a,b):a-b\) is divisible by (3)(}). How many ordered pairs are in (R)?

Correct Answer: A. (6). Explanation: Classes ({1,4},{2},{3}) हैं, इसलिए pairs की संख्या \(2^2+1^2+1^2=6\) है। Equivalence classes के sizes के squares जोड़ें। / The classes are ({1,4},{2},{3}), so the number of pairs is \(2^2+1^2+1^2=6\). Add the squares of the sizes of the equivalence classes.

Which concept should I revise for this Mathematics MCQ?

The classes are ({1,4},{2},{3}), so the number of pairs is \(2^2+1^2+1^2=6\). Add the squares of the sizes of the equivalence classes.

What exam hint can help solve this Mathematics question?

Classes ({1,4},{2},{3}) हैं, इसलिए pairs की संख्या \(2^2+1^2+1^2=6\) है। Equivalence classes के sizes के squares जोड़ें।