फलन (y=(x+2)3-1) में \(y=x^3\) का बिंदु ((0,0)) किस बिंदु पर जाता है?
In (y=(x+2)3-1), where does the point ((0,0)) of \(y=x^3\) move?
Explanation opens after your attempt
A. ((-2,-1))
Concept
The term (x+2) shifts the graph (2) units left and (-1) shifts it down. Hence ((0,0)) becomes ((-2,-1)).
Why this answer is correct
The correct answer is A. ((-2,-1)). The term (x+2) shifts the graph (2) units left and (-1) shifts it down. Hence ((0,0)) becomes ((-2,-1)).
Exam Tip
(x+2) ग्राफ को (2) इकाई बाईं ओर और (-1) नीचे ले जाता है। इसलिए ((0,0)) से ((-2,-1)) मिलता है।
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