\(x_1+x_2+x_3+x_4=16\) में exactly (1) variable zero हो और बाकी positive हों, तो count क्या है?

In \(x_1+x_2+x_3+x_4=16\), if exactly (1) variable is zero and the rest are positive, what is the count?

Explanation opens after your attempt
Correct Answer

A. \(^{4}C_1{}^{15}C_2\)

Step 1

Concept

Choose the zero variable and split positive sum (16) among the remaining (3) variables. In exams convert exactly-zero cases into positive distribution.

Step 2

Why this answer is correct

The correct answer is A. \(^{4}C_1{}^{15}C_2\). Choose the zero variable and split positive sum (16) among the remaining (3) variables. In exams convert exactly-zero cases into positive distribution.

Step 3

Exam Tip

Zero variable चुनें और बाकी (3) variables में positive sum (16) बांटें। परीक्षा में exactly zero cases को positive distribution में बदलें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

\(x_1+x_2+x_3+x_4=16\) में exactly (1) variable zero हो और बाकी positive हों, तो count क्या है? / In \(x_1+x_2+x_3+x_4=16\), if exactly (1) variable is zero and the rest are positive, what is the count?

Correct Answer: A. \(^{4}C_1{}^{15}C_2\). Explanation: Zero variable चुनें और बाकी (3) variables में positive sum (16) बांटें। परीक्षा में exactly zero cases को positive distribution में बदलें। / Choose the zero variable and split positive sum (16) among the remaining (3) variables. In exams convert exactly-zero cases into positive distribution.

Which concept should I revise for this Mathematics MCQ?

Choose the zero variable and split positive sum (16) among the remaining (3) variables. In exams convert exactly-zero cases into positive distribution.

What exam hint can help solve this Mathematics question?

Zero variable चुनें और बाकी (3) variables में positive sum (16) बांटें। परीक्षा में exactly zero cases को positive distribution में बदलें।