तीन समुच्चयों में (n(A)=84), (n(B)=78), (n(C)=72), ठीक एक समुच्चय में (96) और तीनों में (12) हैं। ठीक दो समुच्चयों में कितने तत्व हैं?

In three sets (n(A)=84), (n(B)=78), (n(C)=72), (96) elements are in exactly one set, and (12) are in all three. How many elements are in exactly two sets?

Explanation opens after your attempt
Correct Answer

B. (51)

Step 1

Concept

Total memberships are (84+78+72=234). \(234=96+2x+3\times12\), so (x=51).

Step 2

Why this answer is correct

The correct answer is B. (51). Total memberships are (84+78+72=234). \(234=96+2x+3\times12\), so (x=51).

Step 3

Exam Tip

कुल सदस्यता (84+78+72=234) है। \(234=96+2x+3\times12\), इसलिए (x=51)।

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तीन समुच्चयों में (n(A)=84), (n(B)=78), (n(C)=72), ठीक एक समुच्चय में (96) और तीनों में (12) हैं। ठीक दो समुच्चयों में कितने तत्व हैं? / In three sets (n(A)=84), (n(B)=78), (n(C)=72), (96) elements are in exactly one set, and (12) are in all three. How many elements are in exactly two sets?

Correct Answer: B. (51). Explanation: कुल सदस्यता (84+78+72=234) है। \(234=96+2x+3\times12\), इसलिए (x=51)। / Total memberships are (84+78+72=234). \(234=96+2x+3\times12\), so (x=51).

Which concept should I revise for this Mathematics MCQ?

Total memberships are (84+78+72=234). \(234=96+2x+3\times12\), so (x=51).

What exam hint can help solve this Mathematics question?

कुल सदस्यता (84+78+72=234) है। \(234=96+2x+3\times12\), इसलिए (x=51)।