असमानताओं \(2x+y\leq 16\), \(x+4y\leq 20\), \(x\geq 1\), \(y\geq 0\) से बने क्षेत्र में तिरछी रेखाओं का प्रतिच्छेद कौन सा है?
In the region formed by \(2x+y\leq 16\), \(x+4y\leq 20\), \(x\geq 1\), and \(y\geq 0\), what is the intersection of the slant lines?
Explanation opens after your attempt
Correct Answer
A. (\left\(\frac{44}{7},\frac{24}{7}\right\))
Concept
Solving the two equations gives \(x=\frac{44}{7}\) and \(y=\frac{24}{7}\). Always test the intersection in all inequalities afterward.
Why this answer is correct
The correct answer is A. (\left\(\frac{44}{7},\frac{24}{7}\right\)). Solving the two equations gives \(x=\frac{44}{7}\) and \(y=\frac{24}{7}\). Always test the intersection in all inequalities afterward.
Exam Tip
दोनों समीकरणों को हल करने पर \(x=\frac{44}{7}\) और \(y=\frac{24}{7}\) मिलता है। प्रतिच्छेद को बाद में सभी असमानताओं से जरूर जांचें।
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