पास्कल identity में \(^{8}C_4\) को किन दो भागों में तोड़ा जाएगा?

In Pascal's identity into which two parts will \(^{8}C_4\) be split?

Explanation opens after your attempt
Correct Answer

A. \(^{7}C_4+^{7}C_3\)

Step 1

Concept

Put (n=8) and (r=4) in \(^{n}C_r=^{n-1}C_r+^{n-1}C_{r-1}\). In exams the upper index of both terms decreases by (1).

Step 2

Why this answer is correct

The correct answer is A. \(^{7}C_4+^{7}C_3\). Put (n=8) and (r=4) in \(^{n}C_r=^{n-1}C_r+^{n-1}C_{r-1}\). In exams the upper index of both terms decreases by (1).

Step 3

Exam Tip

\(^{n}C_r=^{n-1}C_r+^{n-1}C_{r-1}\) में (n=8) और (r=4) रखें। परीक्षा में दोनों terms का upper index (1) कम होता है।

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Mathematics Answer, Explanation and Revision Hints

पास्कल identity में \(^{8}C_4\) को किन दो भागों में तोड़ा जाएगा? / In Pascal's identity into which two parts will \(^{8}C_4\) be split?

Correct Answer: A. \(^{7}C_4+^{7}C_3\). Explanation: \(^{n}C_r=^{n-1}C_r+^{n-1}C_{r-1}\) में (n=8) और (r=4) रखें। परीक्षा में दोनों terms का upper index (1) कम होता है। / Put (n=8) and (r=4) in \(^{n}C_r=^{n-1}C_r+^{n-1}C_{r-1}\). In exams the upper index of both terms decreases by (1).

Which concept should I revise for this Mathematics MCQ?

Put (n=8) and (r=4) in \(^{n}C_r=^{n-1}C_r+^{n-1}C_{r-1}\). In exams the upper index of both terms decreases by (1).

What exam hint can help solve this Mathematics question?

\(^{n}C_r=^{n-1}C_r+^{n-1}C_{r-1}\) में (n=8) और (r=4) रखें। परीक्षा में दोनों terms का upper index (1) कम होता है।