\(^{n}C_r=\frac{n}{n-r},^{n-1}C_r\) में कौन-सा lower index समान रहता है?

In \(^{n}C_r=\frac{n}{n-r},^{n-1}C_r\) which lower index remains same?

Explanation opens after your attempt
Correct Answer

C. (r)

Step 1

Concept

The lower index is (r) in both combinations. In exams read upper and lower indices separately.

Step 2

Why this answer is correct

The correct answer is C. (r). The lower index is (r) in both combinations. In exams read upper and lower indices separately.

Step 3

Exam Tip

दोनों combinations में lower index (r) है। परीक्षा में formula पढ़ते समय upper और lower index अलग-अलग देखें।

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Mathematics Answer, Explanation and Revision Hints

\(^{n}C_r=\frac{n}{n-r},^{n-1}C_r\) में कौन-सा lower index समान रहता है? / In \(^{n}C_r=\frac{n}{n-r},^{n-1}C_r\) which lower index remains same?

Correct Answer: C. (r). Explanation: दोनों combinations में lower index (r) है। परीक्षा में formula पढ़ते समय upper और lower index अलग-अलग देखें। / The lower index is (r) in both combinations. In exams read upper and lower indices separately.

Which concept should I revise for this Mathematics MCQ?

The lower index is (r) in both combinations. In exams read upper and lower indices separately.

What exam hint can help solve this Mathematics question?

दोनों combinations में lower index (r) है। परीक्षा में formula पढ़ते समय upper और lower index अलग-अलग देखें।