\(^{n}C_r=\frac{n}{n-r},^{n-1}C_r\) में कौन-सा lower index समान रहता है?
In \(^{n}C_r=\frac{n}{n-r},^{n-1}C_r\) which lower index remains same?
Explanation opens after your attempt
C. (r)
Concept
The lower index is (r) in both combinations. In exams read upper and lower indices separately.
Why this answer is correct
The correct answer is C. (r). The lower index is (r) in both combinations. In exams read upper and lower indices separately.
Exam Tip
दोनों combinations में lower index (r) है। परीक्षा में formula पढ़ते समय upper और lower index अलग-अलग देखें।
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