यदि \(x+y\leq 10\), \(x-y\leq 2\), \(x\geq 0\), \(y\geq 0\) हैं, तो बिंदु ((6,4)) के बारे में सही कथन क्या है?
If \(x+y\leq 10\), \(x-y\leq 2\), \(x\geq 0\), and \(y\geq 0\), which statement about ((6,4)) is correct?
Explanation opens after your attempt
A. यह दोनों तिरछी सीमाओं के प्रतिच्छेद पर स्थित हल हैIt is a solution at the intersection of both slant boundaries
Concept
At ((6,4)), both (x+y=10) and (x-y=2) hold as equalities. So it is the valid intersection of both boundary lines.
Why this answer is correct
The correct answer is A. यह दोनों तिरछी सीमाओं के प्रतिच्छेद पर स्थित हल है / It is a solution at the intersection of both slant boundaries. At ((6,4)), both (x+y=10) and (x-y=2) hold as equalities. So it is the valid intersection of both boundary lines.
Exam Tip
((6,4)) पर (x+y=10) और (x-y=2) दोनों बराबरी देते हैं। इसलिए यह दोनों सीमा-रेखाओं का वैध प्रतिच्छेद है।
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