यदि \(x\in \mathbb{Z}\) और \( \frac{x+2}{3}\geq -1 \) तथा ( 2x-1<9 ), तो (x) के कितने पूर्णांक मान संभव हैं?
If \(x\in \mathbb{Z}\), \( \frac{x+2}{3}\geq -1 \), and ( 2x-1<9 ), how many integer values of (x) are possible?
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Correct Answer
B. (8)
Concept
The first inequality gives \(x\geq -5\), and the second gives (x<5). Integers from (-5) to (4) are (10) in total.
Why this answer is correct
The correct answer is B. (8). The first inequality gives \(x\geq -5\), and the second gives (x<5). Integers from (-5) to (4) are (10) in total.
Exam Tip
पहली असमानता से \(x\geq -5\) और दूसरी से (x<5) मिलता है। पूर्णांक (-5) से (4) तक कुल (10) हैं।
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