यदि \(x\in\mathbb{R}\) और \(2\leq \frac{x+1}{3}<5\) है तो (x) का अंतराल कौन सा है?

If \(x\in\mathbb{R}\) and \(2\leq \frac{x+1}{3}<5\), which interval is for (x)?

Explanation opens after your attempt
Correct Answer

A. ([5,14))

Step 1

Concept

Multiplying by (3) gives \(6\leq x+1<15\), hence \(5\leq x<14\). Removing a positive denominator does not change the signs.

Step 2

Why this answer is correct

The correct answer is A. ([5,14)). Multiplying by (3) gives \(6\leq x+1<15\), hence \(5\leq x<14\). Removing a positive denominator does not change the signs.

Step 3

Exam Tip

(3) से गुणा करने पर \(6\leq x+1<15\) और \(5\leq x<14\) मिलता है। धनात्मक हर हटाने पर चिन्ह नहीं बदलते।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x\in\mathbb{R}\) और \(2\leq \frac{x+1}{3}<5\) है तो (x) का अंतराल कौन सा है? / If \(x\in\mathbb{R}\) and \(2\leq \frac{x+1}{3}<5\), which interval is for (x)?

Correct Answer: A. ([5,14)). Explanation: (3) से गुणा करने पर \(6\leq x+1<15\) और \(5\leq x<14\) मिलता है। धनात्मक हर हटाने पर चिन्ह नहीं बदलते। / Multiplying by (3) gives \(6\leq x+1<15\), hence \(5\leq x<14\). Removing a positive denominator does not change the signs.

Which concept should I revise for this Mathematics MCQ?

Multiplying by (3) gives \(6\leq x+1<15\), hence \(5\leq x<14\). Removing a positive denominator does not change the signs.

What exam hint can help solve this Mathematics question?

(3) से गुणा करने पर \(6\leq x+1<15\) और \(5\leq x<14\) मिलता है। धनात्मक हर हटाने पर चिन्ह नहीं बदलते।