यदि \(x\in\mathbb{R}\) और \(0\leq 4x-8<12\) है तो (x) का अंतराल क्या है?

If \(x\in\mathbb{R}\) and \(0\leq 4x-8<12\), what is the interval for (x)?

Explanation opens after your attempt
Correct Answer

A. ([2,5))

Step 1

Concept

From \(0\leq 4x-8<12\), we get \(8\leq 4x<20\), hence \(2\leq x<5\). Solve both ends of a compound inequality together.

Step 2

Why this answer is correct

The correct answer is A. ([2,5)). From \(0\leq 4x-8<12\), we get \(8\leq 4x<20\), hence \(2\leq x<5\). Solve both ends of a compound inequality together.

Step 3

Exam Tip

\(0\leq 4x-8<12\) से \(8\leq 4x<20\) और \(2\leq x<5\) मिलता है। संयुक्त असमता में दोनों सिरों को साथ-साथ हल करें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x\in\mathbb{R}\) और \(0\leq 4x-8<12\) है तो (x) का अंतराल क्या है? / If \(x\in\mathbb{R}\) and \(0\leq 4x-8<12\), what is the interval for (x)?

Correct Answer: A. ([2,5)). Explanation: \(0\leq 4x-8<12\) से \(8\leq 4x<20\) और \(2\leq x<5\) मिलता है। संयुक्त असमता में दोनों सिरों को साथ-साथ हल करें। / From \(0\leq 4x-8<12\), we get \(8\leq 4x<20\), hence \(2\leq x<5\). Solve both ends of a compound inequality together.

Which concept should I revise for this Mathematics MCQ?

From \(0\leq 4x-8<12\), we get \(8\leq 4x<20\), hence \(2\leq x<5\). Solve both ends of a compound inequality together.

What exam hint can help solve this Mathematics question?

\(0\leq 4x-8<12\) से \(8\leq 4x<20\) और \(2\leq x<5\) मिलता है। संयुक्त असमता में दोनों सिरों को साथ-साथ हल करें।