\(x_1+x_2+x_3+x_4=10\) में हर \(x_i\leq4\) हो, तो valid count किस expression से मिलेगा?

If \(x_1+x_2+x_3+x_4=10\) and every \(x_i\leq4\), which expression gives the valid count?

Explanation opens after your attempt
Correct Answer

A. \(^{13}C_3-4{}^{8}C_3+6{}^{3}C_3\)

Step 1

Concept

A violation begins with \(x_i\geq5\), so inclusion-exclusion applies. In exams use a subtract shift of (5) for upper limit (4).

Step 2

Why this answer is correct

The correct answer is A. \(^{13}C_3-4{}^{8}C_3+6{}^{3}C_3\). A violation begins with \(x_i\geq5\), so inclusion-exclusion applies. In exams use a subtract shift of (5) for upper limit (4).

Step 3

Exam Tip

Violation \(x_i\geq5\) से शुरू होती है और inclusion-exclusion लागू होता है। परीक्षा में upper limit (4) हो तो (5) subtract shift लें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

\(x_1+x_2+x_3+x_4=10\) में हर \(x_i\leq4\) हो, तो valid count किस expression से मिलेगा? / If \(x_1+x_2+x_3+x_4=10\) and every \(x_i\leq4\), which expression gives the valid count?

Correct Answer: A. \(^{13}C_3-4{}^{8}C_3+6{}^{3}C_3\). Explanation: Violation \(x_i\geq5\) से शुरू होती है और inclusion-exclusion लागू होता है। परीक्षा में upper limit (4) हो तो (5) subtract shift लें। / A violation begins with \(x_i\geq5\), so inclusion-exclusion applies. In exams use a subtract shift of (5) for upper limit (4).

Which concept should I revise for this Mathematics MCQ?

A violation begins with \(x_i\geq5\), so inclusion-exclusion applies. In exams use a subtract shift of (5) for upper limit (4).

What exam hint can help solve this Mathematics question?

Violation \(x_i\geq5\) से शुरू होती है और inclusion-exclusion लागू होता है। परीक्षा में upper limit (4) हो तो (5) subtract shift लें।