यदि \(U={x:x\in \mathbb{N},x\le 15}\) और \(M=\{5,10,15\}\) है, तो (M') में कितने अवयव होंगे?
If \(U={x:x\in \mathbb{N},x\le 15}\) and \(M=\{5,10,15\}\), how many elements will be in (M')?
Explanation opens after your attempt
A. (12)
Concept
(n(U)=15) and (n(M)=3), so (n(M')=12). For the number of complement elements, subtract selected elements from the total.
Why this answer is correct
The correct answer is A. (12). (n(U)=15) and (n(M)=3), so (n(M')=12). For the number of complement elements, subtract selected elements from the total.
Exam Tip
(n(U)=15) और (n(M)=3), इसलिए (n(M')=12)। पूरक की संख्या के लिए कुल में से चुने गए अवयव घटाएं।
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