यदि \(U={1,2,\ldots,27}\), \(A={x:x\in U,3\mid x}\), \(B={x:x\in U,9\mid x}\), तो \(A\cap B'\) क्या है?

If \(U={1,2,\ldots,27}\), \(A={x:x\in U,3\mid x}\), and \(B={x:x\in U,9\mid x}\), what is \(A\cap B'\)?

Explanation opens after your attempt
Correct Answer

A. ({3,6,12,15,21,24})

Step 1

Concept

(A) contains multiples of (3) and (B) contains multiples of (9). Thus \(A\cap B'\) contains multiples of (3) that are not multiples of (9).

Step 2

Why this answer is correct

The correct answer is A. ({3,6,12,15,21,24}). (A) contains multiples of (3) and (B) contains multiples of (9). Thus \(A\cap B'\) contains multiples of (3) that are not multiples of (9).

Step 3

Exam Tip

(A) में (3) के गुणज हैं और (B) में (9) के गुणज हैं। इसलिए \(A\cap B'\) में (3) के वे गुणज हैं जो (9) के गुणज नहीं हैं।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(U={1,2,\ldots,27}\), \(A={x:x\in U,3\mid x}\), \(B={x:x\in U,9\mid x}\), तो \(A\cap B'\) क्या है? / If \(U={1,2,\ldots,27}\), \(A={x:x\in U,3\mid x}\), and \(B={x:x\in U,9\mid x}\), what is \(A\cap B'\)?

Correct Answer: A. ({3,6,12,15,21,24}). Explanation: (A) में (3) के गुणज हैं और (B) में (9) के गुणज हैं। इसलिए \(A\cap B'\) में (3) के वे गुणज हैं जो (9) के गुणज नहीं हैं। / (A) contains multiples of (3) and (B) contains multiples of (9). Thus \(A\cap B'\) contains multiples of (3) that are not multiples of (9).

Which concept should I revise for this Mathematics MCQ?

(A) contains multiples of (3) and (B) contains multiples of (9). Thus \(A\cap B'\) contains multiples of (3) that are not multiples of (9).

What exam hint can help solve this Mathematics question?

(A) में (3) के गुणज हैं और (B) में (9) के गुणज हैं। इसलिए \(A\cap B'\) में (3) के वे गुणज हैं जो (9) के गुणज नहीं हैं।