यदि हल-क्षेत्र \(x\geq 2\), \(y\geq 1\), \(x+y\leq 8\) से बनता है, तो उसका क्षेत्रफल कितना है?
If the solution region is formed by \(x\geq 2\), \(y\geq 1\), and \(x+y\leq 8\), what is its area?
Explanation opens after your attempt
Correct Answer
C. \(\frac{25}{2}\) वर्ग इकाई\(\frac{25}{2}\) square units
Concept
The vertices are ((2,1)), ((7,1)), and ((2,6)). The base and height are (5), so the area is \(\frac{25}{2}\).
Why this answer is correct
The correct answer is C. \(\frac{25}{2}\) वर्ग इकाई / \(\frac{25}{2}\) square units. The vertices are ((2,1)), ((7,1)), and ((2,6)). The base and height are (5), so the area is \(\frac{25}{2}\).
Exam Tip
शीर्ष ((2,1)), ((7,1)), ((2,6)) हैं। आधार और ऊंचाई (5) हैं इसलिए क्षेत्रफल \(\frac{25}{2}\) है।
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