यदि हल-क्षेत्र \(x\geq 2\), \(y\geq 1\), \(2x+3y\leq 18\) से बनता है, तो उसका क्षेत्रफल कितना है?
If the solution region is formed by \(x\geq 2\), \(y\geq 1\), and \(2x+3y\leq 18\), what is its area?
Explanation opens after your attempt
B. (15) वर्ग इकाई(15) square units
Concept
The vertices are ((2,1)), (\left\(\frac{15}{2},1\right\)), and (\(2,\frac{14}{3}\)). Check parallel distances carefully before using triangle area.
Why this answer is correct
The correct answer is B. (15) वर्ग इकाई / (15) square units. The vertices are ((2,1)), (\left\(\frac{15}{2},1\right\)), and (\(2,\frac{14}{3}\)). Check parallel distances carefully before using triangle area.
Exam Tip
शीर्ष ((2,1)), (\left\(\frac{15}{2},1\right\)), (\(2,\frac{14}{3}\)) हैं। आधार \(\frac{11}{2}\) और ऊंचाई \(\frac{11}{3}\) से क्षेत्रफल \(\frac{121}{12}\) नहीं बल्कि सही गणना के लिए अक्षों के समांतर दूरी जांचें।
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