यदि \(R=\{(x,y):y=x+1,\ x\in{1,2,3},\ y\in{2,3}\}\), तो (R) \(A=\{1,2,3\}\) से \(B=\{2,3\}\) में function क्यों नहीं है?
If \(R=\{(x,y):y=x+1,\ x\in{1,2,3},\ y\in{2,3}\}\), why is (R) not a function from \(A=\{1,2,3\}\) to \(B=\{2,3\}\)?
Explanation opens after your attempt
A. (x=3) के लिए \(y=4\notin B\), इसलिए image नहीं बनतीFor (x=3), \(y=4\notin B\), so no image is formed
Concept
The required output for (x=3) is (4), which is not in the codomain, so every domain element is not mapped. A codomain restriction can change the relation.
Why this answer is correct
The correct answer is A. (x=3) के लिए \(y=4\notin B\), इसलिए image नहीं बनती / For (x=3), \(y=4\notin B\), so no image is formed. The required output for (x=3) is (4), which is not in the codomain, so every domain element is not mapped. A codomain restriction can change the relation.
Exam Tip
(x=3) का required output (4) codomain में नहीं है, इसलिए domain का हर element mapped नहीं है। codomain restriction relation को बदल सकती है।
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