यदि (^{n}C_r=\frac{^{n}C_{r-1}(n-r+1)}{r}) है तो यह किस तरह की derivation है?

If (^{n}C_r=\frac{^{n}C_{r-1}(n-r+1)}{r}), what kind of derivation is this?

Explanation opens after your attempt
Correct Answer

A. Consecutive combination ratio derivation

Step 1

Concept

It is obtained by taking the ratio of \(^{n}C_r\) and \(^{n}C_{r-1}\). In exams simplify adjacent combinations using factorial ratios.

Step 2

Why this answer is correct

The correct answer is A. Consecutive combination ratio derivation. It is obtained by taking the ratio of \(^{n}C_r\) and \(^{n}C_{r-1}\). In exams simplify adjacent combinations using factorial ratios.

Step 3

Exam Tip

यह \(^{n}C_r\) और \(^{n}C_{r-1}\) का ratio लेकर मिलता है। परीक्षा में adjacent combinations को factorial ratio से simplify करें।

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यदि (^{n}C_r=\frac{^{n}C_{r-1}(n-r+1)}{r}) है तो यह किस तरह की derivation है? / If (^{n}C_r=\frac{^{n}C_{r-1}(n-r+1)}{r}), what kind of derivation is this?

Correct Answer: A. Consecutive combination ratio derivation. Explanation: यह \(^{n}C_r\) और \(^{n}C_{r-1}\) का ratio लेकर मिलता है। परीक्षा में adjacent combinations को factorial ratio से simplify करें। / It is obtained by taking the ratio of \(^{n}C_r\) and \(^{n}C_{r-1}\). In exams simplify adjacent combinations using factorial ratios.

Which concept should I revise for this Mathematics MCQ?

It is obtained by taking the ratio of \(^{n}C_r\) and \(^{n}C_{r-1}\). In exams simplify adjacent combinations using factorial ratios.

What exam hint can help solve this Mathematics question?

यह \(^{n}C_r\) और \(^{n}C_{r-1}\) का ratio लेकर मिलता है। परीक्षा में adjacent combinations को factorial ratio से simplify करें।