यदि (n\(A\cup B\)=70), (n\(A\setminus B\)=22) और (n\(B\setminus A\)=31) है, तो (n\(A\cap B\)) कितना होगा?
If (n\(A\cup B\)=70), (n\(A\setminus B\)=22), and (n\(B\setminus A\)=31), then what is (n\(A\cap B\))?
Explanation opens after your attempt
Correct Answer
A. (17)
Concept
The union is made of three disjoint parts \(A\setminus B\), \(B\setminus A\), and \(A\cap B\). Therefore (n\(A\cap B\)=70-22-31=17).
Why this answer is correct
The correct answer is A. (17). The union is made of three disjoint parts \(A\setminus B\), \(B\setminus A\), and \(A\cap B\). Therefore (n\(A\cap B\)=70-22-31=17).
Exam Tip
संघ तीन असंबद्ध भागों \(A\setminus B\), \(B\setminus A\) और \(A\cap B\) से बनता है। इसलिए (n\(A\cap B\)=70-22-31=17)।
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