यदि (n(A)=94), (n\(A\cap B\)=40), (n\(A\cap C\)=37) और (n\(A\cap B\cap C\)=16) है, तो केवल (A) में आने वाले तत्व कितने हैं?
If (n(A)=94), (n\(A\cap B\)=40), (n\(A\cap C\)=37), and (n\(A\cap B\cap C\)=16), how many elements are only in (A)?
Explanation opens after your attempt
C. (33)
Concept
Only (A=94-40-37+16=33). The central part is subtracted twice, so add it once.
Why this answer is correct
The correct answer is C. (33). Only (A=94-40-37+16=33). The central part is subtracted twice, so add it once.
Exam Tip
केवल (A=94-40-37+16=33) है। केंद्रीय भाग दो बार घटता है, इसलिए उसे एक बार जोड़ें।
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