यदि (n(A)=88), (n(B)=82) और (n\(A\triangle B\)=104) है, तो (n\(A\cap B\)) कितना है?
If (n(A)=88), (n(B)=82), and (n\(A\triangle B\)=104), what is (n\(A\cap B\))?
Explanation opens after your attempt
Correct Answer
B. (33)
Concept
(n\(A\triangle B\)=n(A)+n(B)-2n\(A\cap B\)), so (104=170-2x) gives (x=33). Keep exactly one and common parts separate.
Why this answer is correct
The correct answer is B. (33). (n\(A\triangle B\)=n(A)+n(B)-2n\(A\cap B\)), so (104=170-2x) gives (x=33). Keep exactly one and common parts separate.
Exam Tip
(n\(A\triangle B\)=n(A)+n(B)-2n\(A\cap B\)), इसलिए (104=170-2x) से (x=33)। ठीक एक और साझा भाग अलग रखें।
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