यदि (n(A)=70), (n(B)=62), (n(C)=58), (n\(A\cap B\)=30), (n\(B\cap C\)=24), (n\(C\cap A\)=26), (n\(A\cap B\cap C\)=12), और (n(U)=130) है, तो किसी में भी नहीं कितने हैं?

If (n(A)=70), (n(B)=62), (n(C)=58), (n\(A\cap B\)=30), (n\(B\cap C\)=24), (n\(C\cap A\)=26), (n\(A\cap B\cap C\)=12), and (n(U)=130), how many are in none?

Explanation opens after your attempt
Correct Answer

A. (8)

Step 1

Concept

The union is (70+62+58-30-24-26+12=122), so outside is (130-122=8). Find the union first and then take its complement.

Step 2

Why this answer is correct

The correct answer is A. (8). The union is (70+62+58-30-24-26+12=122), so outside is (130-122=8). Find the union first and then take its complement.

Step 3

Exam Tip

संघ (70+62+58-30-24-26+12=122) है, इसलिए बाहर (130-122=8)। पहले संघ निकालें फिर पूरक लें।

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Mathematics Answer, Explanation and Revision Hints

यदि (n(A)=70), (n(B)=62), (n(C)=58), (n\(A\cap B\)=30), (n\(B\cap C\)=24), (n\(C\cap A\)=26), (n\(A\cap B\cap C\)=12), और (n(U)=130) है, तो किसी में भी नहीं कितने हैं? / If (n(A)=70), (n(B)=62), (n(C)=58), (n\(A\cap B\)=30), (n\(B\cap C\)=24), (n\(C\cap A\)=26), (n\(A\cap B\cap C\)=12), and (n(U)=130), how many are in none?

Correct Answer: A. (8). Explanation: संघ (70+62+58-30-24-26+12=122) है, इसलिए बाहर (130-122=8)। पहले संघ निकालें फिर पूरक लें। / The union is (70+62+58-30-24-26+12=122), so outside is (130-122=8). Find the union first and then take its complement.

Which concept should I revise for this Mathematics MCQ?

The union is (70+62+58-30-24-26+12=122), so outside is (130-122=8). Find the union first and then take its complement.

What exam hint can help solve this Mathematics question?

संघ (70+62+58-30-24-26+12=122) है, इसलिए बाहर (130-122=8)। पहले संघ निकालें फिर पूरक लें।