यदि (n(A)=30), (n(B)=28), (n(C)=24), (n\(A\cap B\)=10), (n\(B\cap C\)=8), (n\(C\cap A\)=6) और (n\(A\cap B\cap C\)=4) है, तो (n\(A\cup B\cup C\)) कितना होगा?
If (n(A)=30), (n(B)=28), (n(C)=24), (n\(A\cap B\)=10), (n\(B\cap C\)=8), (n\(C\cap A\)=6), and (n\(A\cap B\cap C\)=4), what is (n\(A\cup B\cup C\))?
Explanation opens after your attempt
A. (62)
Concept
The formula gives (30+28+24-10-8-6+4=62). For three sets, remember to add back the final common part.
Why this answer is correct
The correct answer is A. (62). The formula gives (30+28+24-10-8-6+4=62). For three sets, remember to add back the final common part.
Exam Tip
सूत्र (30+28+24-10-8-6+4=62) देता है। तीन समुच्चयों में अंतिम साझा भाग वापस जोड़ना याद रखें।
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