यदि (n(A)=30), (n(B)=28), (n(C)=24), (n\(A\cap B\)=10), (n\(B\cap C\)=8), (n\(C\cap A\)=6) और (n\(A\cap B\cap C\)=4) है, तो (n\(A\cup B\cup C\)) कितना होगा?

If (n(A)=30), (n(B)=28), (n(C)=24), (n\(A\cap B\)=10), (n\(B\cap C\)=8), (n\(C\cap A\)=6), and (n\(A\cap B\cap C\)=4), what is (n\(A\cup B\cup C\))?

Explanation opens after your attempt
Correct Answer

A. (62)

Step 1

Concept

The formula gives (30+28+24-10-8-6+4=62). For three sets, remember to add back the final common part.

Step 2

Why this answer is correct

The correct answer is A. (62). The formula gives (30+28+24-10-8-6+4=62). For three sets, remember to add back the final common part.

Step 3

Exam Tip

सूत्र (30+28+24-10-8-6+4=62) देता है। तीन समुच्चयों में अंतिम साझा भाग वापस जोड़ना याद रखें।

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Mathematics Answer, Explanation and Revision Hints

यदि (n(A)=30), (n(B)=28), (n(C)=24), (n\(A\cap B\)=10), (n\(B\cap C\)=8), (n\(C\cap A\)=6) और (n\(A\cap B\cap C\)=4) है, तो (n\(A\cup B\cup C\)) कितना होगा? / If (n(A)=30), (n(B)=28), (n(C)=24), (n\(A\cap B\)=10), (n\(B\cap C\)=8), (n\(C\cap A\)=6), and (n\(A\cap B\cap C\)=4), what is (n\(A\cup B\cup C\))?

Correct Answer: A. (62). Explanation: सूत्र (30+28+24-10-8-6+4=62) देता है। तीन समुच्चयों में अंतिम साझा भाग वापस जोड़ना याद रखें। / The formula gives (30+28+24-10-8-6+4=62). For three sets, remember to add back the final common part.

Which concept should I revise for this Mathematics MCQ?

The formula gives (30+28+24-10-8-6+4=62). For three sets, remember to add back the final common part.

What exam hint can help solve this Mathematics question?

सूत्र (30+28+24-10-8-6+4=62) देता है। तीन समुच्चयों में अंतिम साझा भाग वापस जोड़ना याद रखें।