यदि (n(A)=20), (n(B)=25) और \(A\cap B=\varnothing\), तो ठीक एक समुच्चय में कितने तत्व हैं?
If (n(A)=20), (n(B)=25), and \(A\cap B=\varnothing\), how many elements are in exactly one set?
Explanation opens after your attempt
A. (45)
Concept
In disjoint sets, every element is in exactly one of the sets, so (20+25=45). Here the common part is zero.
Why this answer is correct
The correct answer is A. (45). In disjoint sets, every element is in exactly one of the sets, so (20+25=45). Here the common part is zero.
Exam Tip
असंबद्ध समुच्चयों में हर तत्व ठीक एक ही समुच्चय में होता है, इसलिए (20+25=45)। यहां साझा भाग शून्य है।
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