यदि (n(A)=20), (n(B)=25) और \(A\cap B=\varnothing\), तो ठीक एक समुच्चय में कितने तत्व हैं?

If (n(A)=20), (n(B)=25), and \(A\cap B=\varnothing\), how many elements are in exactly one set?

Explanation opens after your attempt
Correct Answer

A. (45)

Step 1

Concept

In disjoint sets, every element is in exactly one of the sets, so (20+25=45). Here the common part is zero.

Step 2

Why this answer is correct

The correct answer is A. (45). In disjoint sets, every element is in exactly one of the sets, so (20+25=45). Here the common part is zero.

Step 3

Exam Tip

असंबद्ध समुच्चयों में हर तत्व ठीक एक ही समुच्चय में होता है, इसलिए (20+25=45)। यहां साझा भाग शून्य है।

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Mathematics Answer, Explanation and Revision Hints

यदि (n(A)=20), (n(B)=25) और \(A\cap B=\varnothing\), तो ठीक एक समुच्चय में कितने तत्व हैं? / If (n(A)=20), (n(B)=25), and \(A\cap B=\varnothing\), how many elements are in exactly one set?

Correct Answer: A. (45). Explanation: असंबद्ध समुच्चयों में हर तत्व ठीक एक ही समुच्चय में होता है, इसलिए (20+25=45)। यहां साझा भाग शून्य है। / In disjoint sets, every element is in exactly one of the sets, so (20+25=45). Here the common part is zero.

Which concept should I revise for this Mathematics MCQ?

In disjoint sets, every element is in exactly one of the sets, so (20+25=45). Here the common part is zero.

What exam hint can help solve this Mathematics question?

असंबद्ध समुच्चयों में हर तत्व ठीक एक ही समुच्चय में होता है, इसलिए (20+25=45)। यहां साझा भाग शून्य है।