यदि (g(x)=x-1) और ((fg)(x)=x-2-1) है तो (f(x)) क्या होगा?
If (g(x)=x-1) and ((fg)(x)=x-2-1) then what is (f(x))?
Explanation opens after your attempt
A. (x+1), \(x\ne 1\)
Concept
(f(x)=\frac{x-2-1}{x-1}=x+1), but \(x\ne 1\) because (g(x)\ne 0). While finding an unknown factor check the division restriction.
Why this answer is correct
The correct answer is A. (x+1), \(x\ne 1\). (f(x)=\frac{x-2-1}{x-1}=x+1), but \(x\ne 1\) because (g(x)\ne 0). While finding an unknown factor check the division restriction.
Exam Tip
(f(x)=\frac{x-2-1}{x-1}=x+1), पर (g(x)\ne 0) के लिए \(x\ne 1\)। अज्ञात गुणक निकालते समय विभाजन का प्रतिबंध देखें।
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