यदि (g(x)=x-1) और ((fg)(x)=x-2-1) है तो (f(x)) क्या होगा?

If (g(x)=x-1) and ((fg)(x)=x-2-1) then what is (f(x))?

Explanation opens after your attempt
Correct Answer

A. (x+1), \(x\ne 1\)

Step 1

Concept

(f(x)=\frac{x-2-1}{x-1}=x+1), but \(x\ne 1\) because (g(x)\ne 0). While finding an unknown factor check the division restriction.

Step 2

Why this answer is correct

The correct answer is A. (x+1), \(x\ne 1\). (f(x)=\frac{x-2-1}{x-1}=x+1), but \(x\ne 1\) because (g(x)\ne 0). While finding an unknown factor check the division restriction.

Step 3

Exam Tip

(f(x)=\frac{x-2-1}{x-1}=x+1), पर (g(x)\ne 0) के लिए \(x\ne 1\)। अज्ञात गुणक निकालते समय विभाजन का प्रतिबंध देखें।

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Mathematics Answer, Explanation and Revision Hints

यदि (g(x)=x-1) और ((fg)(x)=x-2-1) है तो (f(x)) क्या होगा? / If (g(x)=x-1) and ((fg)(x)=x-2-1) then what is (f(x))?

Correct Answer: A. (x+1), \(x\ne 1\). Explanation: (f(x)=\frac{x-2-1}{x-1}=x+1), पर (g(x)\ne 0) के लिए \(x\ne 1\)। अज्ञात गुणक निकालते समय विभाजन का प्रतिबंध देखें। / (f(x)=\frac{x-2-1}{x-1}=x+1), but \(x\ne 1\) because (g(x)\ne 0). While finding an unknown factor check the division restriction.

Which concept should I revise for this Mathematics MCQ?

(f(x)=\frac{x-2-1}{x-1}=x+1), but \(x\ne 1\) because (g(x)\ne 0). While finding an unknown factor check the division restriction.

What exam hint can help solve this Mathematics question?

(f(x)=\frac{x-2-1}{x-1}=x+1), पर (g(x)\ne 0) के लिए \(x\ne 1\)। अज्ञात गुणक निकालते समय विभाजन का प्रतिबंध देखें।