यदि \(\frac{x-5}{4}<2\) या \(3x+1\le -8\), तो संयुक्त हल क्या है?
If \(\frac{x-5}{4}<2\) or \(3x+1\le -8\), what is the combined solution?
Explanation opens after your attempt
A. (x<13)
Concept
The first inequality gives (x<13), and the second gives \(x\le -3\). The second set is contained in the first, so the answer is (x<13).
Why this answer is correct
The correct answer is A. (x<13). The first inequality gives (x<13), and the second gives \(x\le -3\). The second set is contained in the first, so the answer is (x<13).
Exam Tip
पहली असमानता से (x<13) और दूसरी से \(x\le -3\) मिलता है। दूसरी शर्त पहले हल में शामिल है, इसलिए उत्तर (x<13) है।
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