यदि (\frac{(n+1)!+n!}{(n-1)!}=150) है तो (n) का मान क्या है?

If (\frac{(n+1)!+n!}{(n-1)!}=150) then what is the value of (n)?

Explanation opens after your attempt
Correct Answer

B. (10)

Step 1

Concept

The numerator becomes (n!(n+2)) and division gives (n(n+2)=150). Check carefully because \(10\times12=120\) is not enough.

Step 2

Why this answer is correct

The correct answer is B. (10). The numerator becomes (n!(n+2)) and division gives (n(n+2)=150). Check carefully because \(10\times12=120\) is not enough.

Step 3

Exam Tip

ऊपर (n!(n+2)) बनता है और भाग देने पर (n(n+2)=150) मिलता है। \(10\times12=120\) नहीं इसलिए सावधानी से जाँचें।

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Mathematics Answer, Explanation and Revision Hints

यदि (\frac{(n+1)!+n!}{(n-1)!}=150) है तो (n) का मान क्या है? / If (\frac{(n+1)!+n!}{(n-1)!}=150) then what is the value of (n)?

Correct Answer: B. (10). Explanation: ऊपर (n!(n+2)) बनता है और भाग देने पर (n(n+2)=150) मिलता है। \(10\times12=120\) नहीं इसलिए सावधानी से जाँचें। / The numerator becomes (n!(n+2)) and division gives (n(n+2)=150). Check carefully because \(10\times12=120\) is not enough.

Which concept should I revise for this Mathematics MCQ?

The numerator becomes (n!(n+2)) and division gives (n(n+2)=150). Check carefully because \(10\times12=120\) is not enough.

What exam hint can help solve this Mathematics question?

ऊपर (n!(n+2)) बनता है और भाग देने पर (n(n+2)=150) मिलता है। \(10\times12=120\) नहीं इसलिए सावधानी से जाँचें।