यदि (f(x)=x-2+ax+2) और (g(x)=x-2-2ax+1) हैं तथा ((f-g)(3)=22), तो (a) का मान क्या है?
If (f(x)=x-2+ax+2) and (g(x)=x-2-2ax+1), and ((f-g)(3)=22), what is the value of (a)?
Explanation opens after your attempt
D. \(\frac{7}{3}\)
Concept
(f-g=3ax+1), so ((f-g)(3)=9a+1=22). Therefore \(a=\frac{7}{3}\).
Why this answer is correct
The correct answer is D. \(\frac{7}{3}\). (f-g=3ax+1), so ((f-g)(3)=9a+1=22). Therefore \(a=\frac{7}{3}\).
Exam Tip
(f-g=3ax+1), इसलिए ((f-g)(3)=9a+1=22)। अतः \(a=\frac{7}{3}\) है।
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