यदि (f(x)=|x+2|) और डोमेन ([1,5]) है, तो रेंज क्या होगी?
If (f(x)=|x+2|) and the domain is ([1,5]), what is the range?
Explanation opens after your attempt
A. ([3,7])
Concept
On this domain, (x+2) is positive, so (|x+2|=x+2). Endpoint values give the range ([3,7]).
Why this answer is correct
The correct answer is A. ([3,7]). On this domain, (x+2) is positive, so (|x+2|=x+2). Endpoint values give the range ([3,7]).
Exam Tip
इस डोमेन पर (x+2) धनात्मक है, इसलिए (|x+2|=x+2)। endpoints से रेंज ([3,7]) मिलती है।
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