\(\frac{f}{g}=\frac{(x-2)^2}{x-2}=x-2\) जहाँ \(x\ne 2\), इसलिए \(x=3\) पर मान (1) है। पहले प्रतिबंध फिर मान रखें। / \(\frac{f}{g}=\frac{(x-2)^2}{x-2}=x-2\) where \(x\ne 2\), so at \(x=3\) the value is (1). First note the restriction then substitute.
Mathematics Answer, Explanation and Revision Hints
यदि \(f(x)=x^2-4x+4\) और \(g(x)=x-2\) हैं तो \(\left(\frac{f}{g}\right)(3)\) का मान क्या है? / If \(f(x)=x^2-4x+4\) and \(g(x)=x-2\) then what is the value of \(\left(\frac{f}{g}\right)(3)\)?
Correct Answer: A. (1). Explanation: \(\frac{f}{g}=\frac{(x-2)^2}{x-2}=x-2\) जहाँ \(x\ne 2\), इसलिए \(x=3\) पर मान (1) है। पहले प्रतिबंध फिर मान रखें। / \(\frac{f}{g}=\frac{(x-2)^2}{x-2}=x-2\) where \(x\ne 2\), so at \(x=3\) the value is (1). First note the restriction then substitute.
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