यदि (f(x)=x-2+1) और (g(x)=\frac{1}{x-2+1}) हैं तो ((fg)(x)) का प्रांत क्या है?
If (f(x)=x-2+1) and (g(x)=\frac{1}{x-2+1}) then what is the domain of ((fg)(x))?
Explanation opens after your attempt
Correct Answer
A. \(\mathbb{R})
Concept
Since \(x^2+1>0\) for all real (x), the denominator is never zero. Therefore the domain is \(\mathbb{R}\).
Why this answer is correct
The correct answer is A. \(\mathbb{R}). Since \(x^2+1>0\) for all real (x), the denominator is never zero. Therefore the domain is \(\mathbb{R}\).
Exam Tip
क्योंकि \(x^2+1>0\) सभी वास्तविक (x) के लिए है, हर कभी शून्य नहीं होता। इसलिए प्रांत \(\mathbb{R}\) है।
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