यदि (f(x)=x+1) और (g(x)=\frac{1}{x+1}) हों, तो ((fg)(x)) का value किसके बराबर है?

If (f(x)=x+1) and (g(x)=\frac{1}{x+1}), what is the value of ((fg)(x))?

Explanation opens after your attempt
Correct Answer

A. \(1,\ x\neq -1\)

Step 1

Concept

((fg)(x)=(x+1)\cdot\frac{1}{x+1}=1), but (x=-1) is not allowed. Always check the denominator in a reciprocal function.

Step 2

Why this answer is correct

The correct answer is A. \(1,\ x\neq -1\). ((fg)(x)=(x+1)\cdot\frac{1}{x+1}=1), but (x=-1) is not allowed. Always check the denominator in a reciprocal function.

Step 3

Exam Tip

((fg)(x)=(x+1)\cdot\frac{1}{x+1}=1), पर (x=-1) allowed नहीं है। reciprocal वाली function में denominator check करें।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=x+1) और (g(x)=\frac{1}{x+1}) हों, तो ((fg)(x)) का value किसके बराबर है? / If (f(x)=x+1) and (g(x)=\frac{1}{x+1}), what is the value of ((fg)(x))?

Correct Answer: A. \(1,\ x\neq -1\). Explanation: ((fg)(x)=(x+1)\cdot\frac{1}{x+1}=1), पर (x=-1) allowed नहीं है। reciprocal वाली function में denominator check करें। / ((fg)(x)=(x+1)\cdot\frac{1}{x+1}=1), but (x=-1) is not allowed. Always check the denominator in a reciprocal function.

Which concept should I revise for this Mathematics MCQ?

((fg)(x)=(x+1)\cdot\frac{1}{x+1}=1), but (x=-1) is not allowed. Always check the denominator in a reciprocal function.

What exam hint can help solve this Mathematics question?

((fg)(x)=(x+1)\cdot\frac{1}{x+1}=1), पर (x=-1) allowed नहीं है। reciprocal वाली function में denominator check करें।