यदि (f(x)=\frac{x}{x-1}) और (g(x)=\frac{x}{x+1}) हैं, तो ((f-g)(x)) क्या है?
If (f(x)=\frac{x}{x-1}) and (g(x)=\frac{x}{x+1}), what is ((f-g)(x))?
Explanation opens after your attempt
Correct Answer
A. \( \frac{2x}{x^2-1} \)
Concept
(\frac{x}{x-1}-\frac{x}{x+1}=\frac{x[(x+1)-(x-1)]}{x-2-1}=\frac{2x}{x-2-1}). Keep brackets correct while taking a common denominator.
Why this answer is correct
The correct answer is A. \( \frac{2x}{x^2-1} \). (\frac{x}{x-1}-\frac{x}{x+1}=\frac{x[(x+1)-(x-1)]}{x-2-1}=\frac{2x}{x-2-1}). Keep brackets correct while taking a common denominator.
Exam Tip
(\frac{x}{x-1}-\frac{x}{x+1}=\frac{x[(x+1)-(x-1)]}{x-2-1}=\frac{2x}{x-2-1})। समान हर बनाते समय कोष्ठक सही रखें।
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