(f(x)+1=\frac{x+3}{x-3}+1=\frac{2x}{x-3}), जहाँ \(x\ne 3\)। स्थिर संख्या जोड़ते समय समान हर बनाएँ। / (f(x)+1=\frac{x+3}{x-3}+1=\frac{2x}{x-3}), where \(x\ne 3\). Make a common denominator when adding a constant.
Mathematics Answer, Explanation and Revision Hints
यदि (f(x)=\frac{x+3}{x-3}) है तो (f(x)+1) का सरल रूप क्या है? / If (f(x)=\frac{x+3}{x-3}) then what is the simplified form of (f(x)+1)?
Correct Answer: A. \(\frac{2x}{x-3}), \(x\ne 3\). Explanation: (f(x)+1=\frac{x+3}{x-3}+1=\frac{2x}{x-3}), जहाँ \(x\ne 3\)। स्थिर संख्या जोड़ते समय समान हर बनाएँ। / (f(x)+1=\frac{x+3}{x-3}+1=\frac{2x}{x-3}), where \(x\ne 3\). Make a common denominator when adding a constant.
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