यदि (f(x)=\frac{x+3}{x-3}) है तो (f(x)+1) का सरल रूप क्या है?

If (f(x)=\frac{x+3}{x-3}) then what is the simplified form of (f(x)+1)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{2x}{x-3}), \(x\ne 3\)

Step 1

Concept

(f(x)+1=\frac{x+3}{x-3}+1=\frac{2x}{x-3}), where \(x\ne 3\). Make a common denominator when adding a constant.

Step 2

Why this answer is correct

The correct answer is A. \(\frac{2x}{x-3}), \(x\ne 3\). (f(x)+1=\frac{x+3}{x-3}+1=\frac{2x}{x-3}), where \(x\ne 3\). Make a common denominator when adding a constant.

Step 3

Exam Tip

(f(x)+1=\frac{x+3}{x-3}+1=\frac{2x}{x-3}), जहाँ \(x\ne 3\)। स्थिर संख्या जोड़ते समय समान हर बनाएँ।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\frac{x+3}{x-3}) है तो (f(x)+1) का सरल रूप क्या है? / If (f(x)=\frac{x+3}{x-3}) then what is the simplified form of (f(x)+1)?

Correct Answer: A. \(\frac{2x}{x-3}), \(x\ne 3\). Explanation: (f(x)+1=\frac{x+3}{x-3}+1=\frac{2x}{x-3}), जहाँ \(x\ne 3\)। स्थिर संख्या जोड़ते समय समान हर बनाएँ। / (f(x)+1=\frac{x+3}{x-3}+1=\frac{2x}{x-3}), where \(x\ne 3\). Make a common denominator when adding a constant.

Which concept should I revise for this Mathematics MCQ?

(f(x)+1=\frac{x+3}{x-3}+1=\frac{2x}{x-3}), where \(x\ne 3\). Make a common denominator when adding a constant.

What exam hint can help solve this Mathematics question?

(f(x)+1=\frac{x+3}{x-3}+1=\frac{2x}{x-3}), जहाँ \(x\ne 3\)। स्थिर संख्या जोड़ते समय समान हर बनाएँ।