यदि (f(x)=\frac{x+2}{x}) और (g(x)=\frac{x-2}{x}) हैं, तो (\(f^2-g^2\)(x)) क्या होगा?

If (f(x)=\frac{x+2}{x}) and (g(x)=\frac{x-2}{x}), what is (\(f^2-g^2\)(x))?

Explanation opens after your attempt
Correct Answer

A. \( \frac{8}{x} \)

Step 1

Concept

Here \(f-g=\frac{4}{x}\) and (f+g=2), so \(f^2-g^2=\frac{8}{x}\). The identity (a-2-b-2=(a-b)(a+b)) is very useful.

Step 2

Why this answer is correct

The correct answer is A. \( \frac{8}{x} \). Here \(f-g=\frac{4}{x}\) and (f+g=2), so \(f^2-g^2=\frac{8}{x}\). The identity (a-2-b-2=(a-b)(a+b)) is very useful.

Step 3

Exam Tip

\(f-g=\frac{4}{x}\) और (f+g=2), इसलिए \(f^2-g^2=\frac{8}{x}\)। पहचान (a-2-b-2=(a-b)(a+b)) बहुत उपयोगी है।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\frac{x+2}{x}) और (g(x)=\frac{x-2}{x}) हैं, तो (\(f^2-g^2\)(x)) क्या होगा? / If (f(x)=\frac{x+2}{x}) and (g(x)=\frac{x-2}{x}), what is (\(f^2-g^2\)(x))?

Correct Answer: A. \( \frac{8}{x} \). Explanation: \(f-g=\frac{4}{x}\) और (f+g=2), इसलिए \(f^2-g^2=\frac{8}{x}\)। पहचान (a-2-b-2=(a-b)(a+b)) बहुत उपयोगी है। / Here \(f-g=\frac{4}{x}\) and (f+g=2), so \(f^2-g^2=\frac{8}{x}\). The identity (a-2-b-2=(a-b)(a+b)) is very useful.

Which concept should I revise for this Mathematics MCQ?

Here \(f-g=\frac{4}{x}\) and (f+g=2), so \(f^2-g^2=\frac{8}{x}\). The identity (a-2-b-2=(a-b)(a+b)) is very useful.

What exam hint can help solve this Mathematics question?

\(f-g=\frac{4}{x}\) और (f+g=2), इसलिए \(f^2-g^2=\frac{8}{x}\)। पहचान (a-2-b-2=(a-b)(a+b)) बहुत उपयोगी है।