यदि (f(x)=\frac{x+2}{x-1}) और (g(x)=x-1) हों, तो ((fg)(x)) का simplified form क्या है?
If (f(x)=\frac{x+2}{x-1}) and (g(x)=x-1), what is the simplified form of ((fg)(x))?
Explanation opens after your attempt
Correct Answer
A. \(x+2,\ x\neq 1\)
Concept
((fg)(x)=\frac{x+2}{x-1}(x-1)=x+2), but because of the original (f(x)), \(x\neq 1\). Write the domain restriction with the simplification.
Why this answer is correct
The correct answer is A. \(x+2,\ x\neq 1\). ((fg)(x)=\frac{x+2}{x-1}(x-1)=x+2), but because of the original (f(x)), \(x\neq 1\). Write the domain restriction with the simplification.
Exam Tip
((fg)(x)=\frac{x+2}{x-1}(x-1)=x+2), पर मूल (f(x)) के कारण \(x\neq 1\)। simplification के साथ domain restriction लिखें।
Login to save your score, XP, coins and progress.