समान हर से (f-g=\frac{x-2+4-\(x^2-4\)}{x}=\frac{8}{x})। दूसरे अंश को घटाते समय दोनों चिन्ह बदलते हैं। / With a common denominator, (f-g=\frac{x-2+4-\(x^2-4\)}{x}=\frac{8}{x}). While subtracting the second numerator, both signs change.
Mathematics Answer, Explanation and Revision Hints
यदि (f(x)=\frac{x-2+4}{x}) और (g(x)=\frac{x-2-4}{x}) हैं, तो ((f-g)(x)) क्या है? / If (f(x)=\frac{x-2+4}{x}) and (g(x)=\frac{x-2-4}{x}), what is ((f-g)(x))?
Correct Answer: A. \(\frac{8}{x}\), \(x\ne 0\). Explanation: समान हर से (f-g=\frac{x-2+4-\(x^2-4\)}{x}=\frac{8}{x})। दूसरे अंश को घटाते समय दोनों चिन्ह बदलते हैं। / With a common denominator, (f-g=\frac{x-2+4-\(x^2-4\)}{x}=\frac{8}{x}). While subtracting the second numerator, both signs change.
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