यदि (f(x)=\frac{5}{x-2}+1) है, तो (f(x)) की रेंज क्या है?

If (f(x)=\frac{5}{x-2}+1), what is the range of (f(x))?

Explanation opens after your attempt
Correct Answer

A. \(\mathbb{R}\setminus{1}\)

Step 1

Concept

\(\frac{5}{x-2}\) is never (0), so output (1) is not obtained. In exams a vertical shift changes the excluded value.

Step 2

Why this answer is correct

The correct answer is A. \(\mathbb{R}\setminus{1}\). \(\frac{5}{x-2}\) is never (0), so output (1) is not obtained. In exams a vertical shift changes the excluded value.

Step 3

Exam Tip

\(\frac{5}{x-2}\) कभी (0) नहीं होता, इसलिए (1) आउटपुट नहीं मिलता। परीक्षा में vertical shift से excluded value बदलती है।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\frac{5}{x-2}+1) है, तो (f(x)) की रेंज क्या है? / If (f(x)=\frac{5}{x-2}+1), what is the range of (f(x))?

Correct Answer: A. \(\mathbb{R}\setminus{1}\). Explanation: \(\frac{5}{x-2}\) कभी (0) नहीं होता, इसलिए (1) आउटपुट नहीं मिलता। परीक्षा में vertical shift से excluded value बदलती है। / \(\frac{5}{x-2}\) is never (0), so output (1) is not obtained. In exams a vertical shift changes the excluded value.

Which concept should I revise for this Mathematics MCQ?

\(\frac{5}{x-2}\) is never (0), so output (1) is not obtained. In exams a vertical shift changes the excluded value.

What exam hint can help solve this Mathematics question?

\(\frac{5}{x-2}\) कभी (0) नहीं होता, इसलिए (1) आउटपुट नहीं मिलता। परीक्षा में vertical shift से excluded value बदलती है।