यदि (f(x)=\frac{1}{x}) और (g(x)=x-2) हैं तो (\(f\circ g\)(x)) का प्रांत क्या है?

If (f(x)=\frac{1}{x}) and (g(x)=x-2) then what is the domain of (\(f\circ g\)(x))?

Explanation opens after your attempt
Correct Answer

A. \(\mathbb{R}-{0})

Step 1

Concept

(\(f\circ g\)(x)=f\(x^2\)=\frac{1}{x-2}) so \(x\ne 0\). In composition also check the domain of the outer function.

Step 2

Why this answer is correct

The correct answer is A. \(\mathbb{R}-{0}). (\(f\circ g\)(x)=f\(x^2\)=\frac{1}{x-2}) so \(x\ne 0\). In composition also check the domain of the outer function.

Step 3

Exam Tip

(\(f\circ g\)(x)=f\(x^2\)=\frac{1}{x-2}) इसलिए \(x\ne 0\)। संयोजन में बाहरी फलन का प्रांत भी जाँचें।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\frac{1}{x}) और (g(x)=x-2) हैं तो (\(f\circ g\)(x)) का प्रांत क्या है? / If (f(x)=\frac{1}{x}) and (g(x)=x-2) then what is the domain of (\(f\circ g\)(x))?

Correct Answer: A. \(\mathbb{R}-{0}). Explanation: (\(f\circ g\)(x)=f\(x^2\)=\frac{1}{x-2}) इसलिए \(x\ne 0\)। संयोजन में बाहरी फलन का प्रांत भी जाँचें। / (\(f\circ g\)(x)=f\(x^2\)=\frac{1}{x-2}) so \(x\ne 0\). In composition also check the domain of the outer function.

Which concept should I revise for this Mathematics MCQ?

(\(f\circ g\)(x)=f\(x^2\)=\frac{1}{x-2}) so \(x\ne 0\). In composition also check the domain of the outer function.

What exam hint can help solve this Mathematics question?

(\(f\circ g\)(x)=f\(x^2\)=\frac{1}{x-2}) इसलिए \(x\ne 0\)। संयोजन में बाहरी फलन का प्रांत भी जाँचें।